Like
It likes the tweet whose link is passed in tweet_url.
body: returns data
success_score: api success rate
errors: errors encountered in api
Here is the code:-
- twitter.like(tweet_url='https://twitter.com/whitehatjunior/status/1361262548410982402')
- Parameters
tweet_url (str) – Tweet url which need to be liked
- Returns
{“body”: {}, “success_score”: “100”, “errors”: []}
- Return type
dict